10*(2x-51)^1/3-25=(2x-51)^2/3

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Solution for 10*(2x-51)^1/3-25=(2x-51)^2/3 equation:


x in (-oo:+oo)

(10*(2*x-51)^1)/3-25 = ((2*x-51)^2)/3 // - ((2*x-51)^2)/3

(10*(2*x-51)^1)/3-(((2*x-51)^2)/3)-25 = 0

(10*(2*x-51))/3-(((2*x-51)^2)/3)-25 = 0

(10*(2*x-51))/3+(-1*(2*x-51)^2)/3-25 = 0

(10*(2*x-51))/3+(-1*(2*x-51)^2)/3+(-25*3)/3 = 0

10*(2*x-51)-1*(2*x-51)^2-25*3 = 0

224*x-4*x^2-3111-75 = 0

224*x-4*x^2-3186 = 0

224*x-4*x^2-3186 = 0

2*(112*x-2*x^2-1593) = 0

112*x-2*x^2-1593 = 0

DELTA = 112^2-(-1593*(-2)*4)

DELTA = -200

DELTA < 0

2 = 0

2/3 = 0

2/3 = 0 // * 3

2 = 0

x belongs to the empty set

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